A particle moves along a straight line such that its position $x$ at any time $t$ is given given by.
$x = 2 t^{3} - 12 t^{2} + 6 t + 8$
The velocity of the particle when its acceleration is zero is ( $x$ is in metre and $t$ is in second)

- 6 m / s

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- 12 m / s

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- 18 m / s

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- 3 m / s

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Solution

The correct option is C $- 18 m / s$
correct option $(C)$

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A particle moves along a straight line such that its position x at any time t is given given by.x=2t3−12t2+6t+8 The velocity of the particle when its acceleration is zero is (x is in metre and t is in second)

The correct option is C −18 m/scorrect option (C)

A particle moves along a straight line such that its position $x$ at any time $t$ is given given by.
$x = 2 t^{3} - 12 t^{2} + 6 t + 8$
The velocity of the particle when its acceleration is zero is ( $x$ is in metre and $t$ is in second)

The correct option is C $- 18 m / s$
correct option $(C)$