Question

A particle moves along the curve $y=x^2+2x$, then the point on the curve such that x and y coordinates of the particle changes with same rate is

• A. (1, 3)
• B.
• C.
• D.

Answer 1

The correct option is D

$\frac{dy}{dt}=\frac{dx}{dt}\Rightarrow (2x+2)\frac{dx}{dt}=\frac{dx}{dt}\Rightarrow x=-\frac{1}{2}y=\frac{1}{4}-1=-\frac{3}{4}$