Question

A particle moves along the $X$-axis as
$x=u(t-2s)+a(t-2s{)}^2.$

• A. the initial velocity of the particle is $u$
• B. the acceleration of the particle is $a$
• C. the acceleration of the particle is $2a$
• D. at $t=2$ s particle is at the origin.

Answer 1

The correct option is A the initial velocity of the particle is $u$

$\frac{dx}{dt}=ut2at-4a$
$\frac{d^{2}x}{d{t}^2}=a_{c}cn=2a$
Ans $\to \left(c\right)\left(d\right)$
$x=u(t-2)+a(t-2{)}^2$
$\frac{dx}{dt}=u+2a(t-2).1$
$\frac{dx}{dt}=4at0sec$
$=u+2a(0-2)$
$v=u-4a$