Question

A particle moves along the X axis in such a way that its X cordinates varies with time as x= 2-5t+6t^2. What will be its initial velocity?

Answer 1

Particle is moving along x-axis so displacement is also along x-axis

Now , ⇒ x = 6t²-5t+2

since , V = dx/dt

Differentiating w.r.t. 't'

⇒ v = 6 × 2t - 5

⇒ v = 12t - 5
when t=0
V=-5m/s
So initial velocity =-5 m/s
Negative sign states that velocity decreases with time.