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1st Equation of Motion

A particle mo...

Question

A particle moves along the x-direction with constant acceleration. The displacement, measured form a convenient position, is 2 m at time t = 0 and is zero when t = 10 s. If the velocity of the particle is momentary zero when t = 6s, determine the acceleration a the velocity v when t = 10s.

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Solution

$L e t i n i t i a l v e l o c i t y b e u s o i n 6 s i t s v e l o c i t y b e c o m e s z e r o . v = u + a t \Rightarrow 0 = u + 6 a . . . . . (1) d i s p l a c e m e n t t i l l 10 s i s 0 - 2 = - 2 m - 2 = u t + \frac{1}{2} a t^{2} \Rightarrow - 2 = u \times 10 + \frac{1}{2} a {\times 10}^{2} = 10 u + 50 a \Rightarrow u + 5 a = - 0.2.... (2) s o l v i n g (1) a n d (2) a = 0.2 m / s^{2}$

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