Question

A particle moves along x-axis as x=4(t-2)+a$(t-2{)}^2$ Which of the following is true?

• A. The initial velocity of particle is 4
• B. The acceleration of particle is 2a
• C. The particle is at origin at t = 0
• D. None of these

Answer 1

The correct option is B The acceleration of particle is 2a

x=4(t-2)+a$(t-2{)}^2$

At t=0,x=-8+4a=4a-8

v=$\frac{dx}{dt}$=4+2a(t-2)

t=0,v=4-4a=4(1-a)

But acceleration, a=$\frac{d^{2}x}{d{t}^2}$=2a