Question

A particle moves along $X-$axis from $x=0$ to $x=1m$ under the influence of a force given by $F=3x^2+2x-10$. Work done in the process is:

• A. $+4J$
• B. $-4J$
• C. $+8J$
• D. $-8J$

Answer 1

The correct option is D $-8J$

Given,

$F=3x^2+2x-10$

Work done $=\int F\cdot ds$

$={\int }_0^1({3x}^2+2x-10)dx$

$={\left[\frac{{3x}^3}{3}+\frac{{2x}^2}{2}-10x\right]}_0^1$

$=(1{)}^3+(1{)}^2-10-0$

$=2-10$

$=-8J$