Question

A particle moves along $x$-axis in such a way that its coordinate $x$ varies with time according to the equation $x=2-5t+6t^2$. If the initial velocity of the particle is $v.$ Find $-v.$

Answer 1

$v=\frac{dx}{dt}=-5+12t$

Initial velocity means at $t=0,$ which is $-5+0=-5.$

Thus$,-v=5$