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Question

A particle moves along X-axis in such a way that its coordinate (X) varies with time (T) according to the expression, x=25t+6t2. Then the initial velocity of the particle is


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Solution

Step. 1 Given Data,
x=25t+6t2

Step 2. Formula Used,

The displacement is given as,

x=ut+12at2, u= initial velocity

a = acceleration

t= time

Step 3. Calculating the initial velocity,

Comparing with the given expression,

x=25t+6t2x=5t+6t2+2

x=ut+12at2

5t+6t2+2=ut+12at2

Comparing coefficient of t, we get u=-5m/s,

12at2=6t2a=12m/s2

The initial velocity of the particle is -5m/s.


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