A particle moves along $x -$ axis with speed $6 m / s$ for the first half distance of a journey and the second half distance with a speed $3 m / s$ The average speed in the total journey is :

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Solution

The total time is given as,

$t = t_{1} + t_{2}$

$t = \frac{\frac{d}{2}}{6} + \frac{\frac{d}{2}}{3}$

$t = \frac{d}{4}$

The average speed is given as,

$v = \frac{d}{t}$

$v = \frac{d}{\frac{d}{4}}$

$v = 4 m / s$

Thus, the average speed in the total journey is $4 m / s$ .

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A particle moves along x− axis with speed 6m/s for the first half distance of a journey and the second half distance with a speed 3m/s The average speed in the total journey is :

The total time is given as, t=t1+t2 t=d26+d23 t=d4 The average speed is given as, v=dt v=dd4 v=4m/s Thus, the average speed in the total journey is 4m/s.

A particle moves along $x -$ axis with speed $6 m / s$ for the first half distance of a journey and the second half distance with a speed $3 m / s$ The average speed in the total journey is :

The total time is given as,

$t = t_{1} + t_{2}$

$t = \frac{\frac{d}{2}}{6} + \frac{\frac{d}{2}}{3}$

$t = \frac{d}{4}$

The average speed is given as,

$v = \frac{d}{t}$

$v = \frac{d}{\frac{d}{4}}$

$v = 4 m / s$

Thus, the average speed in the total journey is $4 m / s$ .