Question

A particle moves along Y-axis according to equation y = 3 + 4cos$\omega$ t. The motion of particle is

• A. not SHM
• B. oscillating but not SHM
• C. SHM
• D. translatory

Answer 1

Answer: (C)

SHM

$y=3+4cos\omega t$
$\frac{dy}{dt}=-4wsin\omega t$
$a=\frac{d^{2}y}{d{t}^2}=-4{\omega }^{2}cos\omega t$
$So,a\propto {\omega }^2$
So, it is a SHM because in SHM $a\propto {\omega }^2$