Question

# A particle moves from $$(1, 0, 3)$$ to the point $$(-3, 4, 5)$$, when a force $$\overline {F} = (\hat {i} + 5\hat {k})$$ acts on it. Amount of workdone in Joules is

A
14
B
10
C
6
D
15

Solution

## The correct option is D $$6$$Here ,     $$\vec F=(\hat i+5\hat k)$$As particle moves from point $$(1,0,3)$$ to point $$(-3,4,5)$$ , therefore displacement of particle                   $$\vec d=(-3\hat i+4\hat j+5\hat k)-(\hat i+3\hat k)=(-4\hat i+4\hat j+2\hat k)$$                  $$W=?$$As              $$W=\vec F.\vec d$$Therefore   $$W=(\hat i+5\hat k).(-4\hat i+4\hat j+2\hat k)=-4+10=6J$$Maths

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