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Question
A particle moves from a point (2^i+5^j) to (4^j+3^k) when a force of (4^i+3^j)N is applied. How much work has been done by the force?
A particle moves from a point (2^i+5^j) to (4^j+3^k) when a force of (4^i+3^j)N is applied. How much work has been done by the force?
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Solution
The correct option is B -11J
Displacement of the particle →S=(4^j+3^k)−(2^i+5^j)=−2^i−^j+3^kForce acting on the particle →F=4^i+3^j∴ Work done W=→F.→S=(4^i+3^j).(−2^i−^j+3^k)=−8+(−3)=−11 J
Displacement of the particle →S=(4^j+3^k)−(2^i+5^j)=−2^i−^j+3^k
Force acting on the particle →F=4^i+3^j
∴ Work done W=→F.→S=(4^i+3^j).(−2^i−^j+3^k)=−8+(−3)=−11 J
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