A particle moves from a point →r1=2^i+3^j(m) to another point →r2=3^i+2^j(m) during which a certain force →F=5^i+5^j acts on it. Find the work done by the force on the particle during the displacement.
→r1 = 2^i + 3^j (m)
→r2 = 3^i + 2^j (m)
Particle moves from position 1 to position 2 whose position vectors are given above we know displacement is change in position.
→s = →r2 − →r1
= (3^i + 2^j) − (2^i + 3^j)
→s = ^i . ^j
Also →F = 5^i + 5^j (N)
⇒ w = →F . →s
= (5^i + 5^j) . (^i − ^j)
W = 5 - 5 = 0 Joules