a particle moves from position 3i+2j-k to 14i+13j+9k dur to uniform force of (4i+j+3k)N. if the displacement in meters then work done will be-

Open in App

Solution

$a = 3 i + 2 j - k b = 14 i + 13 j + 9 k s = a - b = 11 i + 11 j + 10 k w o r k d o n e = f . s = (11 i + 11 j + 10 k) . (4 i + j + 3 k) = 44 + 11 + 10 = 65 j o u l e$

Suggest Corrections

Similar questions

Q. If under the action of a force

(4 i + j + 3 k) N

, a particle moves from position

r_{1} = 3 i + 2 j - 6 k

to positions

r_{2} = 14 i + 13 j + 9 k,

then the work done will be :

A particle moves from position vector r1=3i^+2j^-6k^ to position vector r2=14i^+13j^+9k^ under the action of force 4i^+j^ +3k^N.Find the work done.

Q. A particle moves from position

3^i + 2^j - 6^k

14^i + 13^j + 9^k

due to a uniform force of

(4^i +^j + 3^k)

N. If the displacement in m then work done will be

Two forces $ˆ i + ˆ j + ˆ k N and ˆ i + 2 ˆ j + 3 ˆ k N$ act on a particle and displace it from (2,3,4) to point (5,4,3). Displacement is in m. Work done is:

Q. A particle acted on by constant forces

3 i + j - k

and

4 i + j - 3 k

is displaced form the point

i + 2 j + 3 k

5 i + 4 j + k .

Find the total work done by the forces.

Join BYJU'S Learning Program

a particle moves from position 3i+2j-k to 14i+13j+9k dur to uniform force of (4i+j+3k)N. if the displacement in meters then work done will be-

a = 3i+2j-kb = 14i+13j+9ks = a-b = 11i+11j+10kwork done = f.s = 11i+11j+10k.4i+j+3k = 44+11+10= 65 joule

$a = 3 i + 2 j - k b = 14 i + 13 j + 9 k s = a - b = 11 i + 11 j + 10 k w o r k d o n e = f . s = (11 i + 11 j + 10 k) . (4 i + j + 3 k) = 44 + 11 + 10 = 65 j o u l e$