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Work Done When Force Is Varying

A particle mo...

Question

A particle moves from position vector r1=3i^+2j^-6k^ to position vector r2=14i^+13j^+9k^ under the action of force 4i^+j^ +3k^N.Find the work done.

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Solution

Dear student,

Given,

R1 = 3i+2j-6k

R2 = 14i+13j+9k

So their displacement vector, say S = R2 - R1

= 14i+13j+9k - (3i+2j-6k)

= 14i + 13j + 9k - 3i - 2j + 6k

= 11i + 11j + 15k

Force = 4i+j+3k

♦ Work done = F . s

= (4i+j+3k) . (11i + 11j + 15k)

= 411 + 111 + 3*15

= 44 + 11 + 45

=100 J

Therefore, the work done is 100J

Regards

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