A particle moves from the position r-1-3 -2 -6 k- to position r-2-14 -13 -9 k- under the action of a force F-4 - -3 k- The work done by the force is

The correct option is C 100 units r⃗ =r⃗ ⃗_⃗ ⃗2⃗ r⃗ ⃗_⃗ ⃗1⃗ =( 11 î + 11 ĵ + 15 k̂ nbsp;) Work done =F⃗·r⃗ =44+11+45=100 units ...

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Electric Field

A particle mo...

Question

A particle moves from the position $_{1} = 3^i + 2^j - 6^k$ to position $_{2} = 14^i + 13^j + 9^k$ under the action of a force $\to F = 4^i +^j + 3^k$ . The work done by the force is

50 units

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75 units

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100 units

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200 units

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Solution

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Similar questions

_{1} = 3^i + 2^j - 6^k

_{2} = 14^i + 13^j + 9^k

4^i +^j + 3^k

_{1} = 3^i + 2^j - 6^k

_{2} = 14^i + 13^j - 9^k

\to F = 4^i +^j + 3^k

{\to r}_{1} = 3^i + 2^j - 6^k

{\to r}_{2} = 14^i + 13^j - 9^k

(4^i +^j + 3^k)

N

_{1} = (3^i + 2^j - 6^k) m

_{2} = (14^i + 13^j + 9^k) m

(4^i +^j + 3^k) N

{\to r}_{1} = 3^i + 2^j - 6^k

{\to r}_{2} = 14^i + 13^j - 9^k

(4^i +^j + 3^k)

N

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