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Question

A particle moves horizontally in uniform circular motion, over a horizontal xy plane. At one instant, it moves through the point at coordinates (4.00 m, 4.00 m) with a velocity of -5.00^i m/s and an acceleration of + 12.5^j m/s2. What are the x and y coordinates of the center of the circular path?


A

(4, 6)

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B

(4, 2)

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C

(2, 4)

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D

(6, 4)

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Solution

The correct option is A

(4, 6)




since ac points in y direction that means centre should be right above it
We know ac=v2R
12.5=(2)2R
R=2
The centre is 2 units above the point(4,4)
Coordinates of centre =(4,6)


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