A particle moves horizontally in uniform circular motion, over a horizontal xy plane. At one instant, it moves through the point at coordinates (4.00 m, 4.00 m) with a velocity of -5.00^i m/s and an acceleration of + 12.5^j m/s2. What are the x and y coordinates of the center of the circular path?
(4, 6)
since ac points in y direction that means centre should be right above it
We know ac=v2R
12.5=(2)2R
⇒R=2
⇒ The centre is 2 units above the point(4,4)
⇒ Coordinates of centre =(4,6)