A particle moves in 2D motion such that its position and time related to each other as x=t2+10,y=t−1. Find velocity of particle at t=2sec(in m/s)
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Solution
Given: x=t2+10⇒vx=dxdt=2t
so, vx|@t=2sec=2×2=4
Also, y=t−1⇒vy=dydt=1
So, at t=2sec, vy=1
Thus, velocity of particle is given by →v=vx^i+vy^j |→v|=√v2x+v2y=√42+12=√17
Hence, option (C) is correct.