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Question

A particle moves in 2D motion such that its position and time related to each other as x=t2+10,y=t1. Find velocity of particle at t=2 sec (in m/s)

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Solution

Given:
x=t2+10 vx=dxdt=2t
so, vx|@ t=2 sec=2×2=4
Also, y=t1 vy=dydt=1
So, at t=2 sec, vy=1
Thus, velocity of particle is given by
v=vx^i+vy^j
|v|=v2x+v2y=42+12=17
Hence, option (C) is correct.

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