A particle moves in a circle of radius $2.0 c m$ at a speed given by $v = 4 t$ , where $v$ is in $c m / s$ and $t$ in seconds. Find the tangential acceleration at $t = 1 s$ .

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Solution

Tangential acceleration
$a_{t} = \frac{d v}{d t} o r a_{t} = \frac{d}{d t} (4 t) = 4 c m / s^{2}$

i.e., $a_{t}$ is constant or tangential acceleration at $t = 1 s$ is $4 c m / s^{2} .$

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A particle moves in a circle of radius 2.0 cm at a speed given by v = 4t, where v is in cm/s and t is in seconds.
Find the tangential acceleration at t =1 s.
Find total acceleration at t =1 s.

A particle moves in a circle of radius 1 cm at speed given by v = 2t where v is in cm/s and t in seconds.

(a) Find the radial acceleration of the particle at t = 1 s.

(b) Find the tangential acceleration at t = 1 s.

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A particle moves in a circle of radius 2.0cm at a speed given by v=4t, where v is in cm/s and t in seconds. Find the tangential acceleration at t=1s.

Tangential accelerationat=dvdtorat=ddt(4t)=4cm/s2i.e., at is constant or tangential acceleration at t=1s is 4cm/s2.

A particle moves in a circle of radius $2.0 c m$ at a speed given by $v = 4 t$ , where $v$ is in $c m / s$ and $t$ in seconds. Find the tangential acceleration at $t = 1 s$ .

Tangential acceleration
$a_{t} = \frac{d v}{d t} o r a_{t} = \frac{d}{d t} (4 t) = 4 c m / s^{2}$

i.e., $a_{t}$ is constant or tangential acceleration at $t = 1 s$ is $4 c m / s^{2} .$