Question

A particle moves in a circle of radius $2.0$ cm at a speed given by $v=4t$, where $v$ is in cm/s and $t$ is in seconds. Find the tangential acceleration at $t=1$ s.

• A. $4cm/s^2$
• B. $8cm/s^2$
• C. $2cm/s^2$
• D. $6cm/s^2$

Answer 1

The correct option is A $4cm/s^2$

Answer is A.

Tangential Acceleration $a_t=\frac{dv}{dt}$ or $a_t=\frac{d}{dt}\left(4t\right)=4cm/s^2$.

Hence, the tangential acceleration at $t=1s:=$ $4cm/s^2$