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Question

A particle moves in a circle of radius 2 cm at a speed given by v=4t, where v is in cm/s and t is in seconds. Then

A
tangential acceleration at t=1 s is 4 cm/s2
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B
total acceleration at t=1 s is 42 cm/s2
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C
total acceleration at t=1 s is 45 cm/s2
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D
tangential acceleration at t=1 s is 5 cm/s2
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Solution

The correct options are
A tangential acceleration at t=1 s is 4 cm/s2
C total acceleration at t=1 s is 45 cm/s2
Tangential acceleration
at=dvdtat=ddt(4t)=4cm/s2Now for acceleration,ac=v2R=(4)22=8a=a2t+a2c=(4)2+(8)2=45m/s2

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