A particle moves in a circle of radius 2cm at a speed given by v=4t, where v is in cm/s and t is in seconds. Then
A
tangential acceleration at t=1s is 4cm/s2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
total acceleration at t=1s is 4√2cm/s2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
total acceleration at t=1s is 4√5cm/s2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
tangential acceleration at t=1s is 5cm/s2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct options are A tangential acceleration at t=1s is 4cm/s2 C total acceleration at t=1s is 4√5cm/s2 Tangential acceleration at=dvdtat=ddt(4t)=4cm/s2Now for acceleration,ac=v2R=(4)22=8⇒a=√a2t+a2c=√(4)2+(8)2=4√5m/s2