A particle moves in a circle of radius 20 cm. Its linear speed is given by v = 2t, where t is second and v in metre/second. Find the radial and tangential acceleration at t = 3 s.

a_{r} = 1.8 m / s^{2}

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$a_{r} = 180 m / s^{2}$

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$a_{t} = 6 m / s^{2}$

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a_{t} = 2 m / s^{2}

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Solution

The correct option is D $a_{t} = 2 m / s^{2}$
The linear speed at t = 3 s is
v = 2t = 6 m/s
The radial acceleration at t = 3 s is
$a_{r} = \frac{v^{2}}{r} = 180 m / s^{2}$
The tangential acceleration is
$a_{t} = \frac{d v}{d t} = 2 m / s^{2}$

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A particle moves in a circle of radius 20 cm. Its linear speed is given by v = 2t, where t is second and v in metre/second. Find the radial and tangential acceleration at t = 3 s.

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is in

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is in

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t = 3 s

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A particle moves in a circle of radius 1 cm at speed given by v = 2t where v is in cm/s and t in seconds.

(a) Find the radial acceleration of the particle at t = 1 s.

(b) Find the tangential acceleration at t = 1 s.

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A particle moves in a circle of radius 20 cm. Its linear speed is given by v = 2t, where t is second and v in metre/second. Find the radial and tangential acceleration at t = 3 s.

The correct option is D at=2m/s2The linear speed at t = 3 s is v = 2t = 6 m/s The radial acceleration at t = 3 s is ar=v2r=180 m/s2 The tangential acceleration is at=dvdt=2 m/s2

The correct option is D $a_{t} = 2 m / s^{2}$
The linear speed at t = 3 s is
v = 2t = 6 m/s
The radial acceleration at t = 3 s is
$a_{r} = \frac{v^{2}}{r} = 180 m / s^{2}$
The tangential acceleration is
$a_{t} = \frac{d v}{d t} = 2 m / s^{2}$