Question

A particle moves in a circle of radius $R=\frac{21}{22}m$ with constant speed 1m/s. Find,
(a) magnitude of average velocity and (b) magnitude of average acceleration in 2s.

Answer 1

Here Particle completes 1 revolution in 6 sec, so in 2sec it will compete 120 degree

It is uniform circular motion -

$Averagevelocity=\frac{2m}{2s}=1m/s$

hence acceleration is only centripetal:-

$a_c=R{w}^2$

$=\frac{21}{22}\times {\left(\frac{1}{6}\right)}^2$

$=\frac{21}{22}\times \frac{1}{6}\times \frac{1}{6}$

$\frac{7}{264}$ $rev/{\sec }^2$