Question

A particle moves in a circle of the radius $25cm$ at two revolutions per second. The acceleration of the particle in $m/se{c}^2$ is

• A. ${\pi }^2$
• B. $8{\pi }^2$
• C. $4{\pi }^2$
• D. $2{\pi }^2$

Answer 1

The correct option is C $4{\pi }^2$

The angular frequency $\omega =2\pi f=2\pi \times 2=4\pi rad/s$

Thus, tangential acceleration $a_t=0$ as$(\omega =constant)$

The net acceleration is the centripetal acceleration.i.e,

$a_{net}={\omega }^{2}r=16{\pi }^2\times 0.25=4{\pi }^{2}m/s^2$