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Question

# A particle moves in a circular path of radius R. In half the period of revolution its displacement and distance covered are:

A
2R, πR
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B
R, πR
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C
2R, 2πR
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D
R2, πR
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Solution

## The correct option is A 2R, πRStep 1: Distance CalculationLet us consider that the particle starts from point A. In half revolution, the particle will be at the opposite point of diameter( at point B) covering a distance ACB(Refer Figure)Distance in half revolution=ACB=12 (Circumference of circle) =2πR2=πR Step 2: Displacement CalculationDisplacement is the shortest distance between the initial and final positions which is Distance ADB here. Therefore, Displacement: =ADB=Diameter of circle =2R Hence A is the correct option.

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