Question

A particle moves in a circular path with uniform speed $v$ . The change in its velocity on rotating through ${60}^o$ is-

Answer 1

Since the particle is moving in a circular path with uniform speed (scalar) so irrespective of the direction the change in speed is zero.

Velocity is a vector quantity. Hence it is direction dependent quantity.

The change in the vector can be given by using triangle law of vector addition.

$v_1-v_2=\sqrt{v_1^2+v_2^2-2v_1{v}_2\cos {60}^{\circ }}$

By substituting the values in the above equation we get

$v_1-v_2=\sqrt{v_1^2+v_2^2-v_1{v}_2}$

Since the both the speed is $v$

Hence the change in velocity is $v$