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Question

A particle moves in a circular path with uniform speed $$v$$ . The change in its velocity on rotating through $$60^o$$ is-


Solution

Since the particle is moving in a circular path with uniform speed (scalar) so irrespective of the direction the change in speed is zero.

Velocity is a vector quantity. Hence it is direction dependent quantity.

The change in the vector can be given by using triangle law of vector addition.

$${v_1} - {v_2} = \sqrt {v_1^2 + v_2^2 - 2{v_1}{v_2}\cos {{60}^ \circ }} $$

By substituting the values in the above equation we get

$${v_1} - {v_2} = \sqrt {v_1^2 + v_2^2 - {v_1}{v_2}} $$

Since the both the speed is $$v$$

Hence the change in velocity is $$v$$


Physics

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