Question

# A particle moves in a circular path with uniform speed $$v$$ . The change in its velocity on rotating through $$60^o$$ is-

Solution

## Since the particle is moving in a circular path with uniform speed (scalar) so irrespective of the direction the change in speed is zero. Velocity is a vector quantity. Hence it is direction dependent quantity. The change in the vector can be given by using triangle law of vector addition. $${v_1} - {v_2} = \sqrt {v_1^2 + v_2^2 - 2{v_1}{v_2}\cos {{60}^ \circ }}$$ By substituting the values in the above equation we get $${v_1} - {v_2} = \sqrt {v_1^2 + v_2^2 - {v_1}{v_2}}$$ Since the both the speed is $$v$$ Hence the change in velocity is $$v$$Physics

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