MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Equations of Motion

A particle mo...

Question

A particle moves in a plane with constant acceleration in a direction different from the initial velocity. The path of the particle will be

A

A straight line

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

An arc of a circle

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

A parabola

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

D

An ellipse

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
A parabola

The path will be parabolic

Suggest Corrections

thumbs-up

1

Similar questions

Q. A particle moves in the xy-plane with constant acceleration a directed along the negative y-axis. The equation of path of the particle has the form

y = b x - c x^{2},

b

c

are positive constants. The velocity

v

of the particle at the origin of coordinates will be

Q. A particle is projected from the origin in the

x - y

plane. The acceleration of particle in negative

y -

direction is a. If equation of path of the particle is y

y = a x - b x^{2}

, then initial velocity of the particle is

Q. A particle moving with a non-zero velocity and constant acceleration on straight line travels

15 m

3 s

33 m

3 s

in the same direction, find
(i) initial velocity of particle
(ii) acceleration of particle

Q. Two particles

A

B

are moving in same direction on a circular path. Initially particle

A

B

are diametrically opposite to each other. Particle

A

moves with angular velocity

π r a d / s

and angular acceleration

\frac{π}{2} r a d / s^{2}

B

moves with constant angular velocity

2 π r a d / s

. Find the time after which both particles

A

B

Q. Statement - 1 : For a particle undergoing rectilinear motion with constant acceleration, the average velocity cannot be equal for two different time intervals.
Statement -2 : The average velocity of particle moving with constant acceleration in a time interval is

\frac{\to u + \to v}{2}

\to u

is the initial velocity and

\to v

is the final velocity.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

PHYSICS

Watch in App

explore_more_icon

Explore more

Equations of Motion

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon