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Question

A particle moves in a straight line. Its position (in m) as function of time is given by
x=(at2+b)
What is the average velocity in time interval t=3 s to t=5 s in ms1. (Where a and b are constants and a=1 ms2, b=1 m)

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Solution

a=1ms2b=1m
x(t)=t2+1
x(3)=9+1=10m
x(5)=25+1=26m
vavg from t = 3s to t = 5s =x(5)x(3)2
vavg=26102=8m/s

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