You visited us 4 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Uniform Circular Motion

A particle mo...

Question

A particle moves in a straight line so that its velocity at any point is given by , where are constants. The acceleration is

Zero

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Uniform

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Non-uniform

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Indeterminate

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B Uniform
$v^{2} = a + b x \Rightarrow 2 v \frac{d v}{d t} = b \frac{d x}{d t} \Rightarrow 2 v \frac{d v}{d t} = b v \Rightarrow \frac{d v}{d t} = \frac{b}{2}$

Suggest Corrections

Similar questions

Q. A particle moves in a straight line in such a way that its velocity at any point is given by

v^{2} = 2 - 3 x

, where

x

is measured from a fixed point. The acceleration is

Q. A particle moves in a straight line in such a way that its velocity at any point is given by

v^{2} = 2 - 3 x

, where x is measured from a fixed point. The acceleration is

A particle moves along a straight line such that its displacement(s) at any time(t) is given by $S = t^{3} - 3 t^{2} + 2$ . The velocity of the particle when its acceleration zero is?

Q. A particle starts from point

A

moves along a straight line path with an acceleration given by

a = p - q x

, where

p, q

are constants and

x

is distance from point

A

. The particle stops at point

B

. The maximum velocity of the particle is

Q. A particle moves along a straight line such that its displacement at any time

t

is given by

s = (t^{3} - 6 t^{2} + 3 t + 4) m

. The velocity when the acceleration is zero is

Join BYJU'S Learning Program

A particle moves in a straight line so that its velocity at any point is given by , where are constants. The acceleration is

The correct option is B Uniformv2=a+bx⇒2vdvdt=bdxdt⇒2vdvdt=bv⇒dvdt=b2

The correct option is B Uniform
$v^{2} = a + b x \Rightarrow 2 v \frac{d v}{d t} = b \frac{d x}{d t} \Rightarrow 2 v \frac{d v}{d t} = b v \Rightarrow \frac{d v}{d t} = \frac{b}{2}$