wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A particle moves in a straight line with a constant acceleration. It changes its velocity from 10 m/s to 20 m/s while passing through a distance of 135 m in t seconds. The value of t is:-

A
12
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
9
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
10
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1.8
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B. 9.

solution
Applying second eqn of motion, we get
s=ut+at22...(i)
Also from first eqn of motion,
we have
vu=at
a=vut...(ii)
From (i) and (ii), we get
s=ut+(vu)2t
s=(u+v2)t
Here, 135=(10+202)t
t=9s
Thus, option (B) is correct.


1143059_1164375_ans_b26142583d0547499673ecef08579b5e.jpg


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Motion Under Constant Acceleration
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon