A particle moves in a straight line with a constant acceleration. it changes its velocity from $10 m s^{- 1}$ to $20 m s^{- 1}$ while passing through a distance $135 m$ in $t$ seconds. The value of $t$ is

9

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10

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1.8

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Solution

The correct option is B $9$
Given,
$u = 10 m / s$
$v = 20 m / s$
$S = 135 m$
$t = ?$
From 3rd equation of motion,
$2 a s = v^{2} - u^{2}$
$a = \frac{v^{2} - u^{2}}{2 s}$
$a = \frac{20 \times 20 - 10 \times 10}{2 \times 135}$
$a = 1.11 m / s^{2}$
From 1st equation of motion,
$v = u + a t$
$20 = 10 + 1.11 t$
$10 = 1.11 t$
$t = \frac{10}{1.11}$
$t = 9 s e c$
The correct option is A.

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A particle moves in a straight line with a constant acceleration. it changes its velocity from 10 ms−1 to 20 ms−1 while passing through a distance 135 m in t seconds. The value of t is

The correct option is B 9Given,u=10m/sv=20m/sS=135mt=?From 3rd equation of motion,2as=v2−u2a=v2−u22sa=20×20−10×102×135a=1.11m/s2From 1st equation of motion,v=u+at20=10+1.11t10=1.11tt=101.11t=9secThe correct option is A.

A particle moves in a straight line with a constant acceleration. it changes its velocity from $10 m s^{- 1}$ to $20 m s^{- 1}$ while passing through a distance $135 m$ in $t$ seconds. The value of $t$ is