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Question

A particle moves in a straight line with a constant acceleration. It changes its velocity from 10 ms-1 to 20 ms-1 while passing through a distance of 135 m in ‘t’ seconds. The value of t is:


A

12

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B

9

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C

10

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D

1.8

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Solution

The correct option is B

9


Step (1) Given:

The initial velocity, u=10m/s

The final velocity, v=20m/s

Distance covered, s=130m

Step (2) Finding the acceleration of the particle:

From the equations of motion, we know that

vu=ata=(vu)ta=(2010)ta=10t

Step (3) Finding the time taken by the particle:

From the equations of motion, the distance covered by the particle is given by

s=ut+(12)at2Bysubstitutingthecorrespondingvalues,weget135=10t+(12)(10t)t2135=10t+5tWeget,t=9s

Hence, the answer is (B) 9 s


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