A particle moves in a straight line with retardation proportional to its displacement. Its loss in kinetic energy for a displacement ‘x’, is proportional to
A
X2
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B
ex
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C
X
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D
Ln(x)
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Solution
The correct option is A
X2
–a∝xora∝–x⇒ particle is executing SHM ∴ ∴KW=12mω2(A2–x2)∴KE∝x2