A particle moves in one dimension in a conservative force field. The variation of potential energy with distance is as shown in the graph below. If the particle starts to move from rest from the point A. Then
A
The speed is zero at the points A and E
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B
The acceleration vanishes at the points A,B,C,D,E
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C
The acceleration vanishes at the points B,C,D
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D
The speed is maximum at the point D
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Solution
The correct options are A The speed is zero at the points A and E C The acceleration vanishes at the points B,C,D Relation between conservative force and potential energy F=−dVdx As slope of given graph is zero(dVdx=0) at points B,C,D. Force F=−dVdx=ma=0. Hence a=0 at these points.
Speed is maximum at B as the potential energy is minimum at this point.