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Question

A particle moves in the x-y plane such that X=(t2,2t) where t is time and X is the coordinate of the particle . The trajectory of the path is

A
circle
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B
Straight line
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C
parabola
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D
None of these
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Solution

The correct option is C parabola

Given that,

Time =t

X=t2,2t

Now, given co-ordinate of the particle as (t2,2t)

Means at any time t x=t2,y=2t

Now, t=y2

So,

x=(y2)2

4x=y2

Hence, the trajectory of the particle is a parabola with equation y2=4x


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