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Byju's Answer
Standard XII
Physics
Instantaneous Velocity
a particle mo...
Question
a particle moves in the x-y plane with a constant acceleration 8 m/s^2 making an angle 37 with x-axis. At t=0 the particle is at the origin & its velocity is 8 m/s along x-axis. Find velocity & the position of the particle at t=2s.
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Similar questions
Q.
A particle moves in the X-Y plane with a constant acceleration of 1.5
m
s
−
2
in the direction making an angle of 37
0
with the X-axis. At t=0 the particle is at the origin and its velocity is 8.0 m/s along the X-axis. Find the velocity of the particle at time t=4.0 sec
Q.
Velocity in
m
/
s
of a particle moving along
x
−
axis varies with time as
v
=
(
10
+
5
t
−
t
2
)
. At time
t
=
0
,
x
=
0.
Acceleration of particle at
t
=
2
s
is
x
m
/
s
2
, then value of
x
is
Q.
The acceleration of a particle which moves along the positive x-axis varies with its position as shown. If the velocity of the particle is
0.8
m
/
s
at
x
=
0
, the velocity of the particle at
x
=
1.4
is (in m/s).
Q.
A particle is moving in x-y-plane at 2 m/s along x-axis. 2 seconds later, its velocity is 4 m/s in a direction making
60
0
with positive x-axis. Its average acceleration for this period of motion is :
Q.
At time t = 0, a particle is at (2m, 4m). It starts moving towards positive x-axis with constant acceleration 2 m/
s
2
(initial velocity = 0). After 2 s, an additional acceleration of 4 m/
s
2
starts acting on the particle in negative y-direction also. Find after next 2 s
(a) velocity and (b) coordinate of particle.
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