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Byju's Answer

Standard XII

Physics

Average Velocity in 2D Motion

A particle mo...

Question

A particle moves in the $x - y$ plane with only an $x$ -component of acceleration of $2 m s^{- 2}$ . The particle starts from the origin at $t = 0$ with an initial velocity having an $x$ -component of $8 m s^{- 1}$ and $y$ -component of $- 15 m s^{- 1}$ . Velocity of particle after time $t$ is :

[(8 + 2 t)^i - 15^j] m s^{- 1}

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Zero

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2 t^i + 15^j

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Directed along

z

-axis

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Solution

The correct option is A $[(8 + 2 t)^i - 15^j] m s^{- 1}$
Acceleration only affects $^{'} x^{'}$ component.
Using the equation of motion.
$v = u + a t .$
$v_{x} = 8 + 2 t$
Hence velocity is given by:
$V = ((8 + 2 t) i - 15 j) m s^{- 1}$
Hence option A is correct.

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A particle moves in the x−y plane with only an x-component of acceleration of 2ms−2. The particle starts from the origin at t=0 with an initial velocity having an x-component of 8ms−1 and y-component of −15 ms−1. Velocity of particle after time t is :

The correct option is A [(8+2t)^i−15^j] ms−1Acceleration only affects ′x′ component.Using the equation of motion.v=u+at.vx=8+2tHence velocity is given by:V=((8+2t)i−15j)ms−1Hence option A is correct.

A particle moves in the $x - y$ plane with only an $x$ -component of acceleration of $2 m s^{- 2}$ . The particle starts from the origin at $t = 0$ with an initial velocity having an $x$ -component of $8 m s^{- 1}$ and $y$ -component of $- 15 m s^{- 1}$ . Velocity of particle after time $t$ is :

The correct option is A $[(8 + 2 t)^i - 15^j] m s^{- 1}$
Acceleration only affects $^{'} x^{'}$ component.
Using the equation of motion.
$v = u + a t .$
$v_{x} = 8 + 2 t$
Hence velocity is given by:
$V = ((8 + 2 t) i - 15 j) m s^{- 1}$
Hence option A is correct.