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Byju's Answer
Standard IX
Physics
Acceleration
A particle mo...
Question
A particle moves in x-y plane with a velocityV 2y i +4j. Equation of the path followed bythe particle is(1) x y(2) y = VX(3) 4x y2(4) 4y x2
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Similar questions
Q.
A particle is moving with velocity
→
V
=
4
x
^
i
+
4
y
^
j
, then general equation for path of particle is
Q.
If
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=
3
sec
θ
−
2
and
y
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2
, then which of the following equation in
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Q.
A particle projected from origin moves in x-y plane with a velocity
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v
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^
i
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^
j
are the unit vectors along x and y axis. Find the equation of path followed by the particle.
Q.
A particle projected from origin moves in
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−
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plane with a velocity
→
v
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^
i
+
6
x
^
j
, where
^
i
and
^
j
are the unit vectors along
x
and
y
axis. Find the equation of path followed by the particle
Q.
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−
y
plane with a velocity of
→
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=
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i
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^
j
)
m/s
, where
^
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^
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and
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