A particle moves in XY plane such that its position, velocity and acceleration are given by →r=x^i+y^j;→v=vx^i+vy^j;→a=ax^i+ay^j which of the following condition is correct if the particles speed is reducing?
A
xvx+yvx<0
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B
xvx+yvy+yvy>0
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C
axvx+ayvy<0
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D
axvx+ayvy>0
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Solution
The correct option is Caxvx+ayvy<0 For speeding down, the velocity and acceleration vector should have opposite sign →a.→v<0⇒axvx+ayvy<0