A particle moves on a line according to the law s=at2+bt+c. If the displacement after one second is 16 cm, the velocity after 2 seconds is 24 cm/sec and the acceleration is 8 cm/sec2, then (a,b,c)
A
(4,8,4)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
(4,4,8)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
(8,4,4)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
(8,8,4)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A(4,8,4) We have, s=at2+bt+c
when t=1,a+b+c=16 v=dsdt=2at+b
when t=2,4a+b=24
acceleration=dvdt=2a=8⇒a=4,b=8,c=4