CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

A particle moves on the X-axis according to the equation x=A+Bsinω t. The motion is simple harmonic with amplitude.

A

A

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

B

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

A+B

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

B


We are given x=A+B sinω t

We can see that the second term basically is the equation of an SHM with amplitude B. What's the first term doing there? Let's think about it. If it were just B sin ωt, it would be an SHM about the origin. Adding a constant to this entire thing would just shift the mean position from origin to x = A. Now the particle is doing SHM about x = A with an amplitude of B. Yes B! because amplitude is how far the particle goes from the mean position. The new means position is x = A but the particle's max displacement is still B from it!


flag
Suggest Corrections
thumbs-up
7
BNAT
mid-banner-image