Question

A particle moves one quarter of a circle path of radius 20 m in 10 S.The magnitude of average velocity of the particle is

• A. $4.83m/s$
• B. $8.73m/s$
• C. $2.83m/s$
• D. $3.63m/s$

Answer 1

The correct option is C $2.83m/s$

Since particle move one quarter of circle so its displacement will be

$d=\sqrt{r^2+r^2}=\sqrt{2r}$

time taken is $10$ sec.

So, Average velocity $=\frac{20\sqrt{2}}{10}$

$=2\sqrt{2}$

$=2.83$ m/s

$\therefore$ Option $C$ is correct.