Question

A particle moves parallel to $x-$axis with constant velocity $v$ as shown in the figure. The angular velocity of the particle about the origin $\text{O}$

• A. remains constant
• B. continuously increases
• C. continuously decreases
• D. oscillates

Answer 1

The correct option is C continuously decreases


Angular velocity about point $\text{O}$ is
$\omega =\frac{v\sin \theta }{r}=\frac{v\sin \theta }{b/\sin \theta }$
$=\frac{v{\sin }^2\theta }{b}\propto {\sin }^2\theta$
(as $v$ and $b$ are constants)

$\theta$ is decreasing, therefore '$\omega$' will decrease continuously.