CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A particle moves so that its position as a function of time in MKS unit is r=ˆi+4t2ˆj+tˆk. The trajectory of the particle is

A
A parabola
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
An ellipse
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
A circle
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A A parabola
Given,
r=^i+4t2^j+t^k
From the above equation,
x=ct
t=xc. . . . . . . . . . . . (1)
y=4t2
y=4(xc)2
y=(4c2)x2
This is the equation of a parabola.
The correct option is A.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
The Law of Conservation of Mechanical Energy
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon