A particle moving along a circle has velocity →v=2^i+3^j+5^km/s and angular velocity →ω=2^i+2^j−2^k, at a particular instant. The magnitude of centripetal acceleration of the particle is
A
2√114m/s2
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B
0mm/s2
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C
3√114m/s2
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D
4√114m/s2
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Solution
The correct option is A2√114m/s2 Centripetal acceleration aC=rw2=vw =√22+32+52×√22+22+(−2)2 =(√4+9+25)(√4+4+4)=(√38)(√12) =√456=2√114m/s2