A particle moving along a straight line travels half of the distance with uniform speed $30 m / s$ and remaining half of the distance with speed $60$ $m / s$ . The average speed of the particle is

45 m / s

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42 m / s

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40 m / s

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50 m / s

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Solution

The correct option is C $40 m / s$
Let total distance be $2 D$ .
Given, $D = 30 t_{1} = 60 t_{2}$ or, $t_{1} = \frac{D}{30}, t_{2} = \frac{D}{60}$
Thus, average speed= $\frac{2 D}{t_{1} + t_{2}} = \frac{2 D}{\frac{D}{30} + \frac{D}{60}} = 40 m / s$

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A particle moving along a straight line travels half of the distance with uniform speed 30 m/s and remaining half of the distance with speed 60 m/s. The average speed of the particle is

The correct option is C 40 m/sLet total distance be 2D. Given, D=30t1=60t2 or, t1=D30, t2=D60Thus, average speed=2Dt1+t2=2DD30+D60=40 m/s

A particle moving along a straight line travels half of the distance with uniform speed $30 m / s$ and remaining half of the distance with speed $60$ $m / s$ . The average speed of the particle is

The correct option is C $40 m / s$
Let total distance be $2 D$ .
Given, $D = 30 t_{1} = 60 t_{2}$ or, $t_{1} = \frac{D}{30}, t_{2} = \frac{D}{60}$
Thus, average speed= $\frac{2 D}{t_{1} + t_{2}} = \frac{2 D}{\frac{D}{30} + \frac{D}{60}} = 40 m / s$