A particle moving along a straight line with a constant acceleration of - 4 m per second square passes through a point on the line with a velocity of + 8 metre per second at the moment when the distance travelled by the particle in 6 second in 5 seconds
uy=10sin60=53√m/s
⇒t=2uyg=2×53√10=3√s
Sx=uxt+12axt2
1.15=5×t−12a×t2
1.15=5×3√−32a
3a2=5×1.73−1.15=8.65−1.15
3a2=7.5
⇒a=153=5m/s2