Question

A particle moving along a straight line with a constant acceleration of - 4 m per second square passes through a point on the line with a velocity of + 8 metre per second at the moment when the distance travelled by the particle in 6 second in 5 seconds

• A. $5m/s^2$
• B. $6m/s^2$
• C. $8m/s^2$
• D. $2m/s^2$

Answer 1

The correct option is A $5m/s^2$

$uy=10sin60=53\surd m/s$

$\Rightarrow t=2uyg=2\times 53\surd 10=3\surd s$

$Sx=uxt+12ax{t}^2$

$1.15=5\times t-12a\times t^2$

$1.15=5\times 3\surd -32a$

$3a^2=5\times 1.73-1.15=8.65-1.15$

$3a^2=7.5$

$\Rightarrow a=153=5m/s^2$