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Standard XII

Physics

Direction of Instantaneous Velocity

A particle mo...

Question

A particle moving along the x - axis travels first 3m distance with velocity $3 m s^{- 1}$ and the second 3 m distance with velocity $6 m s^{- 1}$ . The average velocity of the particle is

4 m s^{- 1}

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2 m s^{- 1}

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4.5 m s^{- 1}

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6 m s^{- 1}

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Solution

The correct option is D $4 m s^{- 1}$
$¯ ¯¯ ¯ V = \frac{T o t a l d i s tan c e}{t o t a l t i m e}$
$= \frac{6}{1 + 0.5} = \frac{6}{1.5} = 4 m / s^{2}$
hence,
option $(A)$ is correct answer.

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A particle moving along the x - axis travels first 3m distance with velocity 3ms−1 and the second 3 m distance with velocity 6ms−1 . The average velocity of the particle is

The correct option is D 4ms−1¯¯¯¯V=Totaldistancetotaltime=61+0.5=61.5=4m/s2hence,option (A) is correct answer.

A particle moving along the x - axis travels first 3m distance with velocity $3 m s^{- 1}$ and the second 3 m distance with velocity $6 m s^{- 1}$ . The average velocity of the particle is

The correct option is D $4 m s^{- 1}$
$¯ ¯¯ ¯ V = \frac{T o t a l d i s tan c e}{t o t a l t i m e}$
$= \frac{6}{1 + 0.5} = \frac{6}{1.5} = 4 m / s^{2}$
hence,
option $(A)$ is correct answer.