A particle moving in a straight line covers half the distance with speed of 3 m/s. The other half of the distance is covered in two equal time intervals with speed of 4.5 m/s and 7.5 m/s respectively. The average speed of the particle during this motion is
If t1 and 2t2 are the time taken by particle to cover first and second half distance respectively.
t1 = x23 = x6 ....(i)
x1 = 4.5t2 and x2 = 7.5t2
So, x1+x2 = x2⇒ 4.5t2+7.5t2 = x2
t2 = x24 .....(ii)
Total time t = t1+2t2 = x6+x12 = x4
So, average speed = 4 m/sec.